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#!/bin/bash for year in {2000..2050} do num=$(cal $year|awk '{print $6 " " $13 " " $20}'|tr ' ' '\n'|grep -c 13) echo "$year has $num Friday the 13th's" done #oneliner #for year in `seq 2000 2050`;do echo "$year has $(cal $year|awk '{print $6 " " $13 " " $20}'|tr ' ' '\n'|grep -c 13) Friday the 13th's";done
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