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bool possible(int x,vector<int>&a,int k){ int usedWorkers=1; int currentWorkersWorkload=0; int n=a.size(); for(int i=0;i<n;i++){ if(a[i]>x) return false; if(a[i]+currentWorkersWorkload<=x){ currentWorkersWorkload+=a[i]; } else { usedWorkers++; currentWorkersWorkload=a[i]; } } if(usedWorkers<=k)return true; else return false; } void solve(){ // binary search on answer vector<int> arr={10,20,30,40,50,60,70,80,90}; // could be unsorted int n=arr.size(); int k=3; int left=0; int right=1e6;//sum of all elements int ans=1e6; while(left<=right){ int mid=(left+right)/2; if(possible(mid,arr,k)){ ans=mid; right=mid-1; } else left=mid+1; } cout<<ans<<endl; }
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