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#include <iostream>
#include <queue>
using namespace std;

int main() {
    int n, m;
    cin >> n >> m;
    char mat[n][m];
    for(int i = 0; i < n; i++) {
        for(int j = 0; j < m; j++) {
            cin >> mat[i][j];
        }
    }
    // prvo da najdeme kade se naoga S i kade se naoga E
    int si = -1, sj = -1;
    int ei = -1, ej = -1;
    
    for(int i = 0; i < n; i++) {
        for(int j = 0; j < m; j++) {
            if(mat[i][j] == 'S') {
                si = i;
                sj = j;
            }
            if(mat[i][j] == 'E') {
                ei = i;
                ej = j;
            }
        }
    }
    
    bool visited[n][m]; // ke ni kazuva koi polinja sme gi posetile a koi ne
    for(int i = 0; i < n; i++) {
        for(int j = 0; j < m; j++) {
            visited[i][j] = false;
        }
    }
    queue<int> q;
    q.push(si);
    q.push(sj);
    q.push(0); // kolku cekori sum napravil od poleto S do momentalnoto pole
    visited[si][sj] = true;
    
    int di[] = {-1, 1, 0, 0};
    int dj[] = {0,  0,-1, 1};
    while(!q.empty()) {
        int ci = q.front();
        q.pop();
        int cj = q.front();
        q.pop();
        int cekori = q.front();
        q.pop();
        if(mat[ci][cj] == 'E') { // ova znaci deka sme stignale do krajot odnosno do posakuvanata destinacija
            cout << "Od S do E ni trebaat " << cekori << " broj na cekori" << endl;
            break;
        }
        for(int i = 0; i < 4; i++) {
            int ti = ci + di[i];
            int tj = cj + dj[i];
            if(ti >= 0 and ti < n and tj >= 0 and tj < m and mat[ti][tj] != '#' and !visited[ti][tj]) {
                q.push(ti);
                q.push(tj);
                q.push(cekori + 1);
                visited[ti][tj] = true;
            }
        }
    }
    
    return 0;
}
/*
 
 5 5
 .....
 #####
 S....
 E....
 #####
 
 
 5 5
 #..E#
 .....
 ##...
 S....
 #####
 
 Queue: (3, 0)
 (3, 0) --> (3, 1)
 Queue: (3, 1)
 (3, 1) --> (3, 2)
 
 Queue: (3, 2) --> (3, 3); (2, 2)
 
 Queue(3, 3); (2, 2)
 (3, 3) --> (3, 4); (2, 3)
 
 Queue: (2, 2), (3, 4), (2, 3)
 (2, 2) --> (1, 2)
 
 Queue: (3, 4), (2, 3), (1, 2)
 (3, 4) --> (2, 4)
 
 Queue: (2, 3), (1, 2), (2, 4)
 (2, 3) --> (1, 3)
 
 Queue: (1, 2), (2, 4), (1, 3)
 (1, 2) --> (1, 1);  (0, 2)
 
 Queue: (2, 4); (1, 3); (1, 1); (0, 2)
 
 (2, 4) --> (1, 4)
 Queue: (1, 3); (1, 1); (0, 2); (1, 4)
 
 (1, 3) --> (0, 3)
 */