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using namespace std; int main(){ long long n; cin>>n; int niza[n]; for(int i = 0; i < n; i++){ cin>>niza[i]; } long long sz = 0; long long answer = n * (n + 1) / 2; for(int i = 0; i < n; i++) { if(niza[i] != 0) { sz += 1; } else { answer -= ((sz) * (sz + 1) / 2); sz = 0; } } answer -= ((sz) * (sz + 1) / 2); cout << answer << endl; return 0; } /* 5 4, 2, 0, 1, 3 **/
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