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using namespace std; typedef long long ll; int n; ll a[200050]; int main(){ ios_base::sync_with_stdio(false); cin >> n; for(int i = 0; i < n; i++) { cin >> a[i]; } set
st; for(int i = 0; i < n - 1; i++) { st.insert(a[i]); } ll ans = 1e18; for(int i = n - 1; i > 0; i--) { set
::iterator it = st.lower_bound(a[i]); if(it != st.end()) { ans = min(ans, *it - a[i]); } st.erase(st.lower_bound(a[i - 1])); } cout << ans << endl; return 0; }
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